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Math Help - Terminal arm

  1. #1
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    Terminal arm

    The point (-2,3) lies on the terminal arm of position angle

    answer is





    I dont know how to solve this question, I had one where it was simular but gave an equation like y=cotx and I couldnt solve that either.

    I know sin=3 and cos=-2 but that is it.
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  2. #2
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    Quote Originally Posted by brentwoodbc View Post
    The point (-2,3) lies on the terminal arm of position angle

    answer is





    I dont know how to solve this question, I had one where it was simular but gave an equation like y=cotx and I couldnt solve that either.
    I still don't know your question. If you're trying to find \cot \theta, then the answer would be -\frac{2}{3}, because in the cartesian plane, with point (x, y) on the terminal ray, \cot \theta = \frac{x}{y}.

    I know sin=3 and cos=-2 but that is it.
    First, watch your notation. You can't write a trig function without an angle. You must write something like
    \sin \theta = 3 or \cos \theta = -2.
    Second, neither value is possible. Sine or cosine of any angle will be between -1 and 1 inclusive. If you're using the point (x, y) to figure out sine and cosine, you need these definitions:
    \sin \theta = \frac{y}{r} and
    \cos \theta = \frac{x}{r}.

    In other words, you forgot to divide each by r. (r is easy to find, it's just \sqrt{x^2 + y^2}).

    Please clarify your question(s).


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  3. #3
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    Quote Originally Posted by brentwoodbc View Post
    The point (-2,3) lies on the terminal arm of position angle

    answer is given is




    Thats my question how do you solve that.
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  4. #4
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    Quote Originally Posted by brentwoodbc View Post
    Thats my question how do you solve that.
    What you have posted is not clear enough to answer.
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  5. #5
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    I know that is what I thought but it is like question #31 then that.
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