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Math Help - unit circle

  1. #1
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    unit circle

    Im not sure if I can get an answer for this because it was on a test and I dont totally remember but heres what I can remember.

    there was an equation given something like 1/cotΘ.... and quarantines were given like (6,19) (might have been (.6,.19) or something) and the answers given where something like √19/6.

    I know its not alot to work with but how do you solve something that gives quardanates on a unit circle and an equation?
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  2. #2
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    Quote Originally Posted by brentwoodbc View Post
    Im not sure if I can get an answer for this because it was on a test and I dont totally remember but heres what I can remember.

    there was an equation given something like 1/cotΘ.
    cot(1/\theta)= tan(\theta)

    ... and quarantines were given like (6,19) (might have been (.6,.19) or something)
    Oh, "coordinates". However, neither (6, 19) nor (.6, .19) is on the unit circle because neither 6^2+ 19^2 nor .6^2+ .19^2 is equal to 1. (.6, .8) is on the unit circle because .6^2+ .8^2= .36+ .64= 1.0.

    and the answers given where something like √19/6.
    Is that \sqrt{19/6} or \sqrt{19}/6? And what was the question?

    I know its not alot to work with but how do you solve something that gives quardanates on a unit circle and an equation?
    If \theta corresponds to a radius of the unit circle passing through (.8, .6) then
    1) sin(\theta)= .6
    2) cos(\theta)= .8
    3) tan(\theta)= sin(\theta)/cos(\theta)= .6/.8= .75
    4) cot(\theta)= cos(\theta)/sin(\theta)= .8/.6= 1.5
    5) sec(\theta)= 1/cos(\theta)= 1/.8= 1.25
    6) csc(\theta)= 1/sin(\theta)= 1/.6= 5/3 or approximately 1.667

    That's the best I can do.
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  3. #3
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    thanks the question didnt make sense to me.
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