1. ## unit circle

Im not sure if I can get an answer for this because it was on a test and I dont totally remember but heres what I can remember.

there was an equation given something like 1/cotΘ.... and quarantines were given like (6,19) (might have been (.6,.19) or something) and the answers given where something like √19/6.

I know its not alot to work with but how do you solve something that gives quardanates on a unit circle and an equation?

2. Originally Posted by brentwoodbc
Im not sure if I can get an answer for this because it was on a test and I dont totally remember but heres what I can remember.

there was an equation given something like 1/cotΘ.
$cot(1/\theta)= tan(\theta)$

... and quarantines were given like (6,19) (might have been (.6,.19) or something)
Oh, "coordinates". However, neither (6, 19) nor (.6, .19) is on the unit circle because neither $6^2+ 19^2$ nor $.6^2+ .19^2$ is equal to 1. (.6, .8) is on the unit circle because $.6^2+ .8^2= .36+ .64= 1.0$.

and the answers given where something like √19/6.
Is that $\sqrt{19/6}$ or $\sqrt{19}/6$? And what was the question?

I know its not alot to work with but how do you solve something that gives quardanates on a unit circle and an equation?
If $\theta$ corresponds to a radius of the unit circle passing through (.8, .6) then
1) $sin(\theta)= .6$
2) $cos(\theta)= .8$
3) $tan(\theta)= sin(\theta)/cos(\theta)= .6/.8= .75$
4) $cot(\theta)= cos(\theta)/sin(\theta)= .8/.6= 1.5$
5) $sec(\theta)= 1/cos(\theta)= 1/.8= 1.25$
6) $csc(\theta)= 1/sin(\theta)= 1/.6= 5/3$ or approximately 1.667

That's the best I can do.

3. thanks the question didnt make sense to me.