Hi guys

Just have a question about the sin function

If the function is given as sin2(x).

How would i know where it will cut the x-axis (assuming the x axis is denoted as using 'pi')

Cause in the original function: sin(x) if we put in 'pi' into x then it will equal 0.

So now, is there an approach that given the function: sin2(x), that i could know where it cuts the x-axis ie when y = 0?

thanks in advance guys

Forgot to mention:

How can i also find the trig. function values.

Like

sin when (-pi)/4 the value is -squareroot x divded by 2.

How can i also use that to figure out a value like pi/4 given the function sin2x