Just have a question about the sin function
If the function is given as sin2(x).
How would i know where it will cut the x-axis (assuming the x axis is denoted as using 'pi')
Cause in the original function: sin(x) if we put in 'pi' into x then it will equal 0.
So now, is there an approach that given the function: sin2(x), that i could know where it cuts the x-axis ie when y = 0?
thanks in advance guys
Forgot to mention:
How can i also find the trig. function values.
sin when (-pi)/4 the value is -squareroot x divded by 2.
How can i also use that to figure out a value like pi/4 given the function sin2x