1. ## sin rule

find 4 solutions of the equation
(sinx)2 = 1/4 for x between 0degrees and 360degrees..

2. Originally Posted by hi00000
find 4 solutions of the equation
(sinx)2 = 1/4 for x between 0degrees and 360degrees..
This isn't a sine rule question... but I'll solve it...

$\displaystyle \sin^2{x} = \frac{1}{4}$

$\displaystyle \sin{x} = \pm \frac{1}{2}$

So we need to figure out which $\displaystyle x$ satisfy this equation.

The focus angle is $\displaystyle 30^{\circ}$.

In each of the other quadrants, the angles that satisfy this equation are

$\displaystyle 180^{\circ} - 30^{\circ}, 180^{\circ} + 30^{\circ}, 360^{\circ} - 30^{\circ}$.

So the four angles are $\displaystyle \left\{30^{\circ}, 150^{\circ}, 210^{\circ}, 330^{\circ}\right\}$.

3. i'mm yaaa.......??//
anyways thanx 4 that

4. Originally Posted by hi00000
find 4 solutions of the equation
(sinx)2 = 1/4 for x between 0degrees and 360degrees..
$\displaystyle \sin^2x=\sin^2\frac\pi{6}$

$\displaystyle x=n\pi\pm\frac\pi{6}$

For $\displaystyle n=0\ ,\ x=30$
For $\displaystyle n=1\ ,\ x=210\ or\ x= 150$
For $\displaystyle n=2\ ,\ x=330$