We are to assume that this is a right triangle with right angle C? Otherwise it cannot be done.

b is "adjacent" angle A and c is the hypotenuse. cos(A)= b/c so c cos(A)= b, c= b/cos(A)1. If Angle A = 56* 40' and b=22ft. find c.

b is "opposite" angle b and c is the hypotenuse. sin(B)= b/c so c sin(B)= b2. If Angle B = 25* and c = 12 cm find b.

a is "opposite" and b is "adjacent". tan(A)= a/b so A= arctan(a/b).3. If b = 16.3 ft. and a = 21.7 ft. find Angle A.

The first thing you should learn about trig functions is theirThank you so muchdefinition!

sin(x)= "opposite"/"hypotenuse"

cos(x)= "adjacent"/"hypotenuse"

tan(x)= "opposite"/"adjacent"

cot(x)= "adjacent"/"opposite"

sec(x)= "hypotenuse"/"adjacent"

css(x)= "hypotenuse"/"opposite"