# Math Help - Trigonometry-integral

1. ## Trigonometry-integral

Calulate this integral :

2. Originally Posted by dhiab
Calulate this integral :
What have you tried?

3. Originally Posted by dhiab
Calulate this integral :
Hint: break it into the sum of the integrals and then use the following...

$\int{\sin^n{x}\,dx} = -\frac{1}{n}\sin^{n - 1}{x}\cos{x} + \frac{n - 1}{n}\int{\sin^{n - 2}{x}\,dx}$

and

$\int{\cos^n{x}\,dx} = \frac{1}{n}\cos^{n-1}{x}\sin{x} + \frac{n - 1}{n}\int{\cos^{n - 2}{x}\,dx}$.