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Math Help - Trigonometry-integral

  1. #1
    Super Member dhiab's Avatar
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    Trigonometry-integral

    Calulate this integral :
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  2. #2
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    Quote Originally Posted by dhiab View Post
    Calulate this integral :
    What have you tried?
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  3. #3
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    Quote Originally Posted by dhiab View Post
    Calulate this integral :
    Hint: break it into the sum of the integrals and then use the following...

    \int{\sin^n{x}\,dx} = -\frac{1}{n}\sin^{n - 1}{x}\cos{x} + \frac{n - 1}{n}\int{\sin^{n - 2}{x}\,dx}

    and

    \int{\cos^n{x}\,dx} = \frac{1}{n}\cos^{n-1}{x}\sin{x} + \frac{n - 1}{n}\int{\cos^{n - 2}{x}\,dx}.
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