Thread: BEARING/trig problem

From a point P, the ships R, V are observed bearings 325degreesT and 47degreesT respectively, whilst from a point Q 10km due north of P the ships R, V bear 310degreesT and 79degreesT respectively.
i) Show that PQ = 10sin50/sin15 and obtain similar expression for PV

dont realli get how to draw the diagram at all , doesnt make sense to me =/// !!

any help is GREATLY appreciated !!!
thankyou !

Originally Posted by iiharthero

From a point P, the ships R, V are observed bearings 325degreesT and 47degreesT respectively, whilst from a point Q 10km due north of P the ships R, V bear 310degreesT and 79degreesT respectively.
i) Show that PQ = 10sin50/sin15 and obtain similar expression for PV

dont realli get how to draw the diagram at all , doesnt make sense to me =/// !!

any help is GREATLY appreciated !!!
thankyou !

All the angles are measured with respect to the North direction, clockwise!

See attachment.

Hello, iiharthero!

From a point , the ships are observed at 325° and 47°, resp,
while from a point 10km due north of , the ships bear 310° and 79°, resp.

i) Show that and obtain similar expression for .

This is the diagram . . .

Code:

                                            o V
                                        * *
                      |              *  *
    R o               |           *   *
        * *           |        *    *
          *   *   50° | 79° *     *
            *     *   |  *      *
              *       oQ      *
                *     |     *
                  *35°|47°*
                    * | *
                      o
                      P

where


Consider and all its angles.

Code:

    R o
        * *
          *15°*           |
            *     *   50° |
              *       *   |
                *    130° o Q
                  *       |
                    *     |10
                      *35°|
                        * |
                          o
                          P

Law of Sines: .

Since , we have: .