From a point P, the ships R, V are observed bearings 325degreesT and 47degreesT respectively, whilst from a point Q 10km due north of P the ships R, V bear 310degreesT and 79degreesT respectively.
i) Show that PQ = 10sin50/sin15 and obtain similar expression for PV
dont realli get how to draw the diagram at all , doesnt make sense to me =/// !!
any help is GREATLY appreciated !!!
From a point , the ships are observed at 325° and 47°, resp,
while from a point 10km due north of , the ships bear 310° and 79°, resp.
i) Show that and obtain similar expression for .
This is the diagram . . .
whereCode:o V * * | * * R o | * * * * | * * * * 50° | 79° * * * * | * * * oQ * * | * *35°|47°* * | * o P
Consider and all its angles.Code:R o * * *15°* | * * 50° | * * | * 130° o Q * | * |10 *35°| * | o P
Law of Sines: .
Since , we have: .