tanA/(secA-1) - tanA(secA+1) = 2cotA please helppp !!! keep gettin stuckkkk !! any help greatly appreciateddd ! thankuu !!
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$\displaystyle tan A[\frac{1}{sec A-1}-\frac{1}{sec A+1}]$ $\displaystyle =tan A[\frac{2}{sec ^2A-1}]$ $\displaystyle =tan A[\frac{2}{tan^2A}]$ $\displaystyle =2cot A$
THANKS alexmahone! appreciate it =D
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