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  1. #1
    Super Member dhiab's Avatar
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    equation

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  2. #2
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    if you are just after the number of solutions for sin(x) = \frac{x}{100} rather than the solutions themselves, you can just sketch them and count how many times they intersect.
    Last edited by pickslides; May 31st 2009 at 03:42 PM. Reason: typo
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  3. #3
    Super Member dhiab's Avatar
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    hello : put f(x)=sin(x) and g(x)=x/100
    study the intersection of two graphs f,g
    remark: -1 <= sin(x) <=1
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  4. #4
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    Quote Originally Posted by dhiab View Post
    remark: -1 <= sin(x) <=1
    I think you mean this is the range?
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  5. #5
    Super Member dhiab's Avatar
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    I think :-1<= x/100<=1
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  6. #6
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    i'm pretty sure for \frac{x}{100} , x \in \Re
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  7. #7
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    this might give you more of idea....
    Attached Files Attached Files
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  8. #8
    Super Member dhiab's Avatar
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    conclusion
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  9. #9
    Super Member dhiab's Avatar
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    Quote Originally Posted by pickslides View Post
    this might give you more of idea....
    it is the ntersection of segement of right and not a right with the graph of function sin (x) xest coach between-100 and 100
    100=33pi pi=3.14
    -33 pi <= x <= 33 pi
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