Hi folks, I can't get the superscript working so have to attach a word doc. Sorry!
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Originally Posted by s_ingram Hi folks, I can't get the superscript working so have to attach a word doc. Sorry! All your considerations and calculations are OK and I can't imagine how you've got the first result because: $\displaystyle \arctan\left(\dfrac1{\sqrt{2}} \right)\approx 35.2644^\circ$ Grüezzi!
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