1. solving trig equations

Hi folks,

I can't get the superscript working so have to attach a word doc. Sorry!

2. Originally Posted by s_ingram
Hi folks,

I can't get the superscript working so have to attach a word doc. Sorry!
All your considerations and calculations are OK and I can't imagine how you've got the first result because:

$\arctan\left(\dfrac1{\sqrt{2}} \right)\approx 35.2644^\circ$

Grüezzi!