Use Law of Cosines with side lengths 7 and 9, and angle measure 84 deg.
(Make sure your calculator is in degrees)
Hey, I have a trig question that I am stuck on and would appreciate any help, Thanks.
Two sides of a parallelogram measure 7.0 cm and 9.0 cm. The longer
diagonal is 12.0 cm long.
a) calculate all the interior angles.
b) How long is the other diagonal?
The answer page got for a) 96 and 84 degrees. for b) 10.8cm
I got the correct degrees, but I can't get 10.8cm.
I used the cosine law, maybe i'm doing it wrong. This is what I did.
A------------------D For some reason I can't draw the pic , but D and C are connected as well as A and B. (parrallelogram)
With a line from A to C which is 12.0cm.
And a line from B to D which I need to figure out.
I used Angle BDC
c^2 = b^2 + d^2 - 2bd cosC
144 = 130 - 126cosC
130-144 = -126cosC
-14 = -126cosC
-14/-126 = cosC
0.1111... = cosC
c= 83 degrees
but how can it be 83 degrees if its obtuse? what did i do wrong? did I draw it wrong?