Write the line parallel to the line with the equation x-5y=6 and through point (10,2) in standard form.
If anyone can explain this to me, i would greatly appreciate it.
Standard form for a line is where is the slope of the line. So in order for the line you want to be parallel to x-5y=6, it needs to have the same slope. Solving this equation by subracting x from both sides and then dividing by -5 we get so so so the slope is
So our line needs to be y=mx+b and we now know
now we need it to go through the point (10,2), so we can plug that point into the equation to solve for b. 10 is x and 2 is y so and solving for b,
So which is parallel to the given line and contains the point (10,2)
To get it in standard form simply subtract from both sides to get