hia, does anyone know the substitution they used to get this: Questions is find the solutions for this, 1=$\displaystyle 2cos^2(2x)-sin(2x)$ and they got $\displaystyle 2sin^2(2x)+sin(2x)$ thanks!!?
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What are you solving for?
just says find all the solutions from 0 to 2pi,, answers in terms of pi cant see how they got that second expression though,(ie in the solutions??) any clue?
Maybe i'm misunderstanding, solutions for what? x? All I can say at the moment is that $\displaystyle 2sin^2(2x) + sin(2x) = 2 - (2cos^2(2x) - sin(2x))$
i menat $\displaystyle \theta$ instead of x and if that is the case what youve said then surely theyre solution is wrong ''.
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