trig substitution?

**i_zz_y_ill** · May 18th 2009, 01:41 PM

hia, does anyone know the substitution they used to get this:

Questions is find the solutions for this, 1= $2cos^2(2x)-sin(2x)$ and they got $2sin^2(2x)+sin(2x)$

thanks!!?

**derfleurer** · May 18th 2009, 01:47 PM

What are you solving for?

**i_zz_y_ill** · May 18th 2009, 01:49 PM

just says find all the solutions from 0 to 2pi,, answers in terms of pi cant see how they got that second expression though,(ie in the solutions??) any clue?

**derfleurer** · May 18th 2009, 01:59 PM

Maybe i'm misunderstanding, solutions for what? x?

All I can say at the moment is that

$2sin^2(2x) + sin(2x) = 2 - (2cos^2(2x) - sin(2x))$

**i_zz_y_ill** · May 18th 2009, 02:08 PM

i menat $\theta$ instead of x and if that is the case what youve said then surely theyre solution is wrong ''.

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