So I seen a problem that said ((a^2-b^2-c^2)/-2bc)=CosA He wants to solve for A but the problem is that in the computer program there is no inverse cos. Is there a way that we are able to solve this problem with out taking the inverse?
Thanks
So I seen a problem that said ((a^2-b^2-c^2)/-2bc)=CosA He wants to solve for A but the problem is that in the computer program there is no inverse cos. Is there a way that we are able to solve this problem with out taking the inverse?
Thanks