A ship leaves base and sails 30 km on a bearing of 034. It is then ordered to take up position due North of the base in exactly 1 hour's time. If the ship has a speed of 20km/h, find the two possible bearings it could take.
A ship leaves base and sails 30 km on a bearing of 034. It is then ordered to take up position due North of the base in exactly 1 hour's time. If the ship has a speed of 20km/h, find the two possible bearings it could take.
In the attached diagram, the ship's two possible courses are given by and . Then use the Sine Rule:
Welcome to Math Help Forum!In the attached diagram, the ship's two possible courses are given by and . Then use the Sine Rule:
There are then two possible values of and
So the two possible courses to steer are and .
Grandad
Oh thanks alot !! i drew the thing but didnt know what to do lol. Thanks.
One question: How come you took 57 away from 180 to get the other value? i dont understand that
Oh thanks alot !! i drew the thing but didnt know what to do lol. Thanks.
One question: How come you took 57 away from 180 to get the other value? i dont understand that
I don't know how much you know about sines and cosines, but amng the rules are, for any value of :
which tells you how to find the sine and cosine of obtuse angles. So, for example, (and ). Check these out on your calculator if you like.