# Math Help - General Solutions

1. ## General Solutions

I want to find the general solutions from this equation

Sin3xCos2x = Cos4xSin2x

Thank You

2. sin3x.cos2x= (1/2).(sin(5x)+ sin(x))
sina.cosb=(1/2)(sin(a+b)+ sin(a-b)) you can use this

3. I had already tried that formula out and swaped them around. Then I put them into the first form to see if any of them could cancel each other out but that didn't work at all.

4. Originally Posted by TomTom
I want to find the general solutions from this equation

Sin3xCos2x = Cos4xSin2x

Thank You
$
\sin 3x \cos 2x = \cos 4x \sin 2x$
$
\implies \sin 5x + \sin x = \sin 6x - \sin 2x \implies \sin 5x + \sin 2x = \sin 6x - \sin x$

Now if you write it as product, you will be able to cancel
However note that cancelling means you will be losing solutions. So seperately solve for the common factor later