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Math Help - General Solutions

  1. #1
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    Red face General Solutions

    I want to find the general solutions from this equation
    Can anyone help me please??

    Sin3xCos2x = Cos4xSin2x

    Thank You
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  2. #2
    Junior Member bebrave's Avatar
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    sin3x.cos2x= (1/2).(sin(5x)+ sin(x))
    sina.cosb=(1/2)(sin(a+b)+ sin(a-b)) you can use this
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  3. #3
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    I had already tried that formula out and swaped them around. Then I put them into the first form to see if any of them could cancel each other out but that didn't work at all.
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  4. #4
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    Quote Originally Posted by TomTom View Post
    I want to find the general solutions from this equation
    Can anyone help me please??

    Sin3xCos2x = Cos4xSin2x

    Thank You
    <br />
\sin 3x \cos 2x = \cos 4x \sin 2x <br />
\implies \sin 5x + \sin x = \sin 6x - \sin 2x \implies \sin 5x + \sin 2x = \sin 6x - \sin x

    Now if you write it as product, you will be able to cancel
    However note that cancelling means you will be losing solutions. So seperately solve for the common factor later
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