I want to find the general solutions from this equation
Can anyone help me please??
Sin3xCos2x = Cos4xSin2x
Thank You
$\displaystyle
\sin 3x \cos 2x = \cos 4x \sin 2x$$\displaystyle
\implies \sin 5x + \sin x = \sin 6x - \sin 2x \implies \sin 5x + \sin 2x = \sin 6x - \sin x$
Now if you write it as product, you will be able to cancel
However note that cancelling means you will be losing solutions. So seperately solve for the common factor later