[SOLVED] Help with simple Trig Identity Q

**demo1** · May 12th 2009, 06:56 PM

sinx + tanx
__________ = tanx
cosx + 1

Thanks!

**TwistedOne151** · May 12th 2009, 07:14 PM

$\frac{\sin{x}+\tan{x}}{\cos{x}+1}=\frac{\sin{x}\fr ac{\cos{x}}{\cos{x}}+\tan{x}}{\cos{x}+1}$
$=\frac{\cos{x}\frac{\sin{x}}{\cos{x}}+\tan{x}}{\co s{x}+1}$
$=\frac{\cos{x}\tan{x}+\tan{x}}{\cos{x}+1}$
you should be able to continue from here.

--Kevin C.

**skeeter** · May 12th 2009, 07:16 PM

Originally Posted by demo1

sinx + tanx
__________ = tanx
cosx + 1

Thanks!

manipulating the numerator on the left side ...

$\sin{x} + \tan{x}$

$\frac{\sin{x}\cos{x}}{\cos{x}} + \frac{\sin{x}}{\cos{x}}$

$\frac{\sin{x}\cos{x} + \sin{x}}{\cos{x}}$

$\frac{\sin{x}(\cos{x} + 1)}{\cos{x}}$

now divide the last expression by the denominator in the original fraction

**demo1** · May 12th 2009, 07:31 PM

thanks!

**demo1** · May 12th 2009, 07:33 PM

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