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Math Help - [SOLVED] Help with simple Trig Identity Q

  1. #1
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    [SOLVED] Help with simple Trig Identity Q

    sinx + tanx
    __________ = tanx
    cosx + 1

    Thanks!
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  2. #2
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    \frac{\sin{x}+\tan{x}}{\cos{x}+1}=\frac{\sin{x}\fr  ac{\cos{x}}{\cos{x}}+\tan{x}}{\cos{x}+1}
    =\frac{\cos{x}\frac{\sin{x}}{\cos{x}}+\tan{x}}{\co  s{x}+1}
    =\frac{\cos{x}\tan{x}+\tan{x}}{\cos{x}+1}
    you should be able to continue from here.

    --Kevin C.
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  3. #3
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    Quote Originally Posted by demo1 View Post
    sinx + tanx
    __________ = tanx
    cosx + 1

    Thanks!
    manipulating the numerator on the left side ...

    \sin{x} + \tan{x}

    \frac{\sin{x}\cos{x}}{\cos{x}} + \frac{\sin{x}}{\cos{x}}

    \frac{\sin{x}\cos{x} + \sin{x}}{\cos{x}}

    \frac{\sin{x}(\cos{x} + 1)}{\cos{x}}

    now divide the last expression by the denominator in the original fraction
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  4. #4
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    thanks!
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  5. #5
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    Solved
    Last edited by demo1; May 12th 2009 at 08:08 PM.
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