Originally Posted by

**AlderDragon** The question reads:

Solve triangle *ABC* if *A* = 75°, *a* = 5, and *b* = 7.

a) *B* = 43.6°, *C* = 61.4°, *c* = 6.4

b) *B* = 136.4°, *C* = 31.6°, *c* = 2.7

c) *B* = 46.4°, *C* = 58.6°, *c* = 4.4

d) no solution

First, I try to solve for angle B:

$\displaystyle

\frac {a} {\sin A} = \frac {b} {\sin B}

$

$\displaystyle

\frac {5} {\sin75} = \frac {7} {\sin B}

$

$\displaystyle

5 \sin B = 7\sin 75

$

$\displaystyle

\sin B = \frac {7sin 75} {5}

$

$\displaystyle

\sin B = 1.3523

$

$\displaystyle

\sin^-1 (1.3523) = $ Undefined

So is the answer "No Solution"? Or, did I make a mistake?