I'm never going to get this...

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- May 7th 2009, 03:54 PMcasey_kMy Biggest Trig Identity Challenge
I'm never going to get this...

- May 7th 2009, 04:34 PMskeeter
$\displaystyle \sin(\pi+x) + \cos\left(\frac{\pi}{2} - x\right) + \tan\left(\frac{\pi}{2} + x\right) =$

$\displaystyle \left[\sin(\pi)\cos(x) + \cos(\pi)\sin(x)\right] + \left[\cos\left(\frac{\pi}{2}\right)\cos(x) + \sin\left(\frac{\pi}{2}\right)\sin(x)\right] + \frac{\sin\left(\frac{\pi}{2} + x\right)}{\cos\left(\frac{\pi}{2} + x\right)} =$

finish up by evaluating the first two expansions, then expand the sine and cosine sum in the last fractional term ... finally simplify. - May 7th 2009, 04:49 PMcasey_kRe:
Thank you so much! I didn't think it was possible!(Happy)