Results 1 to 2 of 2

Thread: Trig identities

  1. #1
    Junior Member casey_k's Avatar
    Joined
    Oct 2008
    From
    Ontario
    Posts
    40

    Trig identities

    how do u prove tan x = csc 2x - cot 2x?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    16,216
    Thanks
    3702
    $\displaystyle \csc(2x) - \cot(2x) =$

    $\displaystyle \frac{1}{\sin(2x)} - \frac{\cos(2x)}{\sin(2x)} =$

    $\displaystyle \frac{1 - \cos(2x)}{\sin(2x)} =$

    $\displaystyle \frac{1 - (1 - 2\sin^2{x})}{2\sin{x}\cos{x}} =$

    $\displaystyle \frac{\sin^2{x}}{\sin{x}\cos{x}} =$

    $\displaystyle \frac{\sin{x}}{\cos{x}} = \tan{x}$
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Trig Identities
    Posted in the Calculus Forum
    Replies: 2
    Last Post: Dec 3rd 2009, 06:44 AM
  2. Trig identities
    Posted in the Trigonometry Forum
    Replies: 6
    Last Post: Jun 22nd 2009, 06:58 AM
  3. Trig Identities
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: Nov 9th 2008, 04:35 PM
  4. Trig Identities
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: Nov 7th 2008, 08:25 PM
  5. Trig Identities Help!!!!
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: Apr 14th 2008, 11:47 AM

Search Tags


/mathhelpforum @mathhelpforum