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Thread: Trig identities

  1. May 7th 2009, 02:10 PM #1
    casey_k
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    Trig identities

    how do u prove tan x = csc 2x - cot 2x?
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  2. May 7th 2009, 02:40 PM #2
    skeeter
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    \csc(2x) - \cot(2x) =

    \frac{1}{\sin(2x)} - \frac{\cos(2x)}{\sin(2x)} =

    \frac{1 - \cos(2x)}{\sin(2x)} =

    \frac{1 - (1 - 2\sin^2{x})}{2\sin{x}\cos{x}} =

    \frac{\sin^2{x}}{\sin{x}\cos{x}} =

    \frac{\sin{x}}{\cos{x}} = \tan{x}
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