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Math Help - Trig Identities

  1. #1
    Junior Member casey_k's Avatar
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    Post Trig Identities

    csc x - sin x = cot x csc x

    I expanded the left side and ended up with 1-sin^2 x/sin x then i turned it into cos^2 x/ sin x and I don't know what to do next because I'm not getting the other side.
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  2. #2
    Junior Member casey_k's Avatar
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  3. #3
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    Hello, casey_k!

    There must be a typo . . . The statement is not an indentity.


    Could it be: . \csc x - \sin x \:=\: \cot x\,{\color{blue}\cos x}


    \csc x - \sin x \;=\;\frac{1}{\sin x} - \sin x \:=\:\frac{1-\sin^2 x}{\sin x} \;=\;\frac{\cos^2\!x}{\sin x} \;=\;\frac{\cos x}{\sin x}\cdot\cos x \;=\;\cot x\cos x

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  4. #4
    Junior Member casey_k's Avatar
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    Re: Typo

    I really hope it's a typo because now I can solve the problem! I'll ask my teacher about it tomorrow and thank you so much!
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