csc x - sin x = cot x csc x
I expanded the left side and ended up with 1-sin^2 x/sin x then i turned it into cos^2 x/ sin x and I don't know what to do next because I'm not getting the other side.
Hello, casey_k!
There must be a typo . . . The statement is not an indentity.
Could it be: . $\displaystyle \csc x - \sin x \:=\: \cot x\,{\color{blue}\cos x}$
$\displaystyle \csc x - \sin x \;=\;\frac{1}{\sin x} - \sin x \:=\:\frac{1-\sin^2 x}{\sin x} \;=\;\frac{\cos^2\!x}{\sin x} \;=\;\frac{\cos x}{\sin x}\cdot\cos x \;=\;\cot x\cos x$