Using the formula for tan(a+b) = [tan(a) +tan(b)]\[1-tan(a)tan(b)]

-17/6 = [8 + tan(b)]/[1-8tan(b)]

-17[1-8tan(b)] = 6[8+tan(b)]

-17 +136 tan(b) = 48 + 6tan(b)

130tan(b) = 65

tan(b) =.5

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- May 6th 2009, 05:38 AM #1

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- May 6th 2009, 06:05 AM #2

- May 6th 2009, 08:39 AM #3

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- May 6th 2009, 08:47 AM #4

- May 6th 2009, 01:56 PM #5

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