If A = 45 degrees and B = arcsin(3/5), find the exact value of csc (A - B).

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- May 5th 2009, 09:21 PMmagentaritacsc (A - B)
If A = 45 degrees and B = arcsin(3/5), find the exact value of csc (A - B).

- May 5th 2009, 09:33 PMProve It
- May 6th 2009, 05:20 AMmagentaritaYes but...
- May 6th 2009, 02:42 PMProve It
- May 7th 2009, 06:11 AMmagentaritaok
I will play with this question and get back to you later.

- May 7th 2009, 06:15 AMmr fantastic
Note that $\displaystyle B = \arcsin \left( \frac{3}{5}\right) \Rightarrow \sin B = \frac{3}{5}$.

And $\displaystyle \sin B = \frac{3}{5} \Rightarrow \cos B = \frac{4}{5}$ (the postive value is taken because the range of the arcsin function is angles in the 4th and 1st quadrants and cos is postive in these two quadrants).