Need help before final

**coasterguy** · May 5th 2009, 05:55 PM

I'm trying to figure out how to do these, but I'm lost:

Suppose A is in Quadrant IV and tan A = B. Write each one of the following values in terms of B.

cotA=
secA=
cosA=
sinA=
cot(90°-A)=
sin(2A)=

__________________________________________________ ________________________________________

Find all solutions Θ, 0° <= Θ < 360°

cos(3Θ + 15°) = 1/2

Thanks!

**Shyam** · May 5th 2009, 06:06 PM

Originally Posted by coasterguy

I'm trying to figure out how to do these, but I'm lost:

Thanks!

$\cot A = \frac{1}<br /> {{\tan A}} = \frac{1}<br /> {B} \hfill \\$

$\sec A = \sqrt {1 + \tan ^2 A} \hfill \\$

$\cos A = \frac{1}<br /> {{\sec A}} \hfill \\$

Finish it all.

**Shyam** · May 5th 2009, 06:11 PM

Originally Posted by coasterguy

cos(3Θ + 15°) = 1/2

Thanks!

$\cos \left( {3\theta + 15^\circ } \right) = \frac{1}<br /> {2} \hfill \\$

$3\theta + 15^\circ = 60^\circ \hfill \\$

finish it.

${\text{OR}} \hfill \\$

$3\theta + 15^\circ = 300^\circ \hfill \\$

finish it.

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