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Thread: Need help before final

  1. #1
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    Need help before final

    I'm trying to figure out how to do these, but I'm lost:

    Suppose A is in Quadrant IV and tan A = B. Write each one of the following values in terms of B.

    cotA=
    secA=
    cosA=
    sinA=
    cot(90°-A)=
    sin(2A)=

    __________________________________________________ ________________________________________

    Find all solutions Θ, 0° <= Θ < 360°
    cos(3Θ + 15°) = 1/2


    Thanks!
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  2. #2
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    Quote Originally Posted by coasterguy View Post
    I'm trying to figure out how to do these, but I'm lost:

    Thanks!
    $\displaystyle \cot A = \frac{1}
    {{\tan A}} = \frac{1}
    {B} \hfill \\$

    $\displaystyle \sec A = \sqrt {1 + \tan ^2 A} \hfill \\$

    $\displaystyle \cos A = \frac{1}
    {{\sec A}} \hfill \\ $

    Finish it all.
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  3. #3
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    Quote Originally Posted by coasterguy View Post

    cos(3Θ + 15°) = 1/2


    Thanks!
    $\displaystyle \cos \left( {3\theta + 15^\circ } \right) = \frac{1}
    {2} \hfill \\$

    $\displaystyle 3\theta + 15^\circ = 60^\circ \hfill \\$

    finish it.

    $\displaystyle {\text{OR}} \hfill \\$

    $\displaystyle 3\theta + 15^\circ = 300^\circ \hfill \\ $

    finish it.
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