Right-Angled Trigonometry

**mexicool27** · May 2nd 2009, 05:56 PM

I attached a file with this post see it for the questions

**skeeter** · May 3rd 2009, 06:30 AM

Originally Posted by mexicool27

I attached a file with this post see it for the questions

what have you tried for this list of problems?

**mexicool27** · May 3rd 2009, 11:32 AM

I dont have to try these question I'm busy on other questions

**mexicool27** · May 3rd 2009, 12:33 PM

I dont even understand 1 word of it i need help

**skeeter** · May 3rd 2009, 12:54 PM

Originally Posted by mexicool27

I dont have to try these question I'm busy on other questions

suit yourself.

**VonNemo19** · May 3rd 2009, 01:35 PM

What seems to be the problem here mexicool?

Tell me what you're mainly having trouble with and I'll do my best to help.

In regards to question three:

$\tan35=\frac{1200}{x}$
$x=\frac{1200}{\tan35}$

**VonNemo19** · May 3rd 2009, 02:59 PM

In regards to 2-a:

First find the measure of BC by the pythagorean theorem $a^2+b^2=c^2$

so what do ya need? Well, you need $BC^2+BD^2=CD^2$

but $BC=\sqrt{(16)^2-(7+4)^2}$

once you have found that value, you plug what you know into the above formula to find $CD$ .

Then with this information, the Law Of Cosines tells us that if we have 3 sides of an oblique triangle, we can know the value of the angles.

Here's the formula

so let $AC=a$ and let $CD=b$ and let $AD=c$ where cosine of gamma = $\cos{C}$

Plug all this stuff in and slove your triangle!

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