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Math Help - Right-Angled Trigonometry

  1. #1
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    Right-Angled Trigonometry

    I attached a file with this post see it for the questions
    Attached Files Attached Files
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  2. #2
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    Quote Originally Posted by mexicool27 View Post
    I attached a file with this post see it for the questions
    what have you tried for this list of problems?
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  3. #3
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    I dont have to try these question I'm busy on other questions
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  4. #4
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    I dont even understand 1 word of it i need help
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  5. #5
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    Quote Originally Posted by mexicool27 View Post
    I dont have to try these question I'm busy on other questions
    suit yourself.
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  6. #6
    No one in Particular VonNemo19's Avatar
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    What seems to be the problem here mexicool?

    Tell me what you're mainly having trouble with and I'll do my best to help.

    In regards to question three:

    \tan35=\frac{1200}{x}
    x=\frac{1200}{\tan35}
    Last edited by mr fantastic; May 3rd 2009 at 06:31 PM. Reason: Merged posts
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  7. #7
    No one in Particular VonNemo19's Avatar
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    In regards to 2-a:

    First find the measure of BC by the pythagorean theorem a^2+b^2=c^2

    so what do ya need? Well, you need BC^2+BD^2=CD^2

    but BC=\sqrt{(16)^2-(7+4)^2}

    once you have found that value, you plug what you know into the above formula to find CD.

    Then with this information, the Law Of Cosines tells us that if we have 3 sides of an oblique triangle, we can know the value of the angles.

    Here's the formula


    so let AC=aand let CD=band let AD=cwhere cosine of gamma = \cos{C}

    Plug all this stuff in and slove your triangle!
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