Let the distance he was initially away from the base of the tree be x

then tan41.1=o/x and tan35.5=o/(x+30)

solving for o in both equations yields

(tan41.1)(x)=o and (tan35.5)(x+30)=o

and since o=o

(tan41.1)(x)=(tan35.5)(x+30)

can you take it from here?