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Math Help - Trig Identities

  1. #1
    Newbie
    Joined
    Apr 2009
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    10

    Trig Identities

    I'm stuck on these trig identities and I was wondering if anyone else could figure them out?? The first time I typed them in they were kinda hard to understand so I hope I did a better job this time.


    (secX/sinX) - (2sinX/cosX) = cotX - tanX


    (tanX-sinX) / sin(cubed)X = secx / (1 + cosX)


    (cosX + 1)/(secX -tanX) - (1-cosX)/(secX + tanX) = 2(1+tanX)


    1 + 3sin(squared)Xsec(to the 4th)X = sec(to the 6th)X - tan(to the 6th)X


    1 + (2/tanX+cotX) + (1/sec(squared)X +csc(squared)X) = (1 + sinXcosX)(squared)
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  2. #2
    MHF Contributor
    Joined
    Nov 2008
    From
    France
    Posts
    1,458
    Hi

    Here is the first one

    \frac{\sec x}{\sin x} - 2 \frac{\sin x}{\cos x} = \frac{1}{\cos x \sin x} - 2 \frac{\sin^2 x}{\cos x \sin x} = \frac{1-2\sin^2 x}{\cos x \sin x} = \frac{1-\sin^2 x-\sin^2 x}{\cos x \sin x}

    \frac{\sec x}{\sin x} - 2 \frac{\sin x}{\cos x} = \frac{\cos^2 x-\sin^2 x}{\cos x \sin x} = \frac{\cos^2 x}{\cos x \sin x} - \frac{\sin^2 x}{\cos x \sin x} = \frac{\cos x}{\sin x} - \frac{\sin x}{\cos x}
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