If "bearing" means what I think it means, the interior angle of the triangle at A is 26 degrees and the interior angle of the triangle at B is 32 degrees. Is that right?Edit: No! The angles are 64 degrees and 58 degrees.In that case, I suggest you draw a line from C to a point D on the AB line chosen so that AB and CD are perpendicular.

CD/AD=tan(26 degrees)

CD/DB=tan(32 degrees)

AD+DB=50 m

Solve this for CD and use that CD=BC sin(32 degrees) and CD=AC sin(26 degrees).

Alternative method? This is the only one I can think of right now.