1. X Terminates in What Quadrant?

If $(sec x - 2)(2 sec x - 1) = 0$ , then x terminates in:

a) Quadrants I and II, only

b) Quadrants I and IV, only

c) Quadrants I, II, III, and IV

2. hello

Solve for x, and determine the domain my son.

3. Hmm...I'm really not sure how to go about solving for x. Also, how would I determine the domain once I have x?

4. When you solve a quadratic equation, in some cases you factor. Right.

Well your problem looks a lot like something like this: (X+a)(X+b)=0

and the solutions are: x=-a, x=-b

Can you see my meaning?

5. Originally Posted by VonNemo19
When you solve a quadratic equation, in some cases you factor. Right.

Well your problem looks a lot like something like this: (X+a)(X+b)=0

and the solutions are: x=-a, x=-b

Can you see my meaning?
So the domain would be the point (2,1), right? That point is located in the first quadrant, giving me the answer of "d".

6. Let secx = y
therfore, y = 2 & y = 1/2
Because both values are positive they are in the 1st and 4th quadrant.

in the first quadrant everything is positive, in second quadrant only sin/cosec is positive, in the third quadrant only tan/cot is positive and in 4th quadrant cos/sec is positive.

Is that what u were askin?

7. So the correct answer is choice "b"?

8. yes

yes

9. Okay, thank you.