# X Terminates in What Quadrant?

• Apr 29th 2009, 03:26 PM
ThaBeretta
If $(sec x - 2)(2 sec x - 1) = 0$ , then x terminates in:

a) Quadrants I and II, only

b) Quadrants I and IV, only

c) Quadrants I, II, III, and IV

• Apr 29th 2009, 03:28 PM
VonNemo19
hello
Solve for x, and determine the domain my son.(Wink)
• Apr 29th 2009, 03:34 PM
ThaBeretta
Hmm...I'm really not sure how to go about solving for x. Also, how would I determine the domain once I have x?
• Apr 29th 2009, 03:41 PM
VonNemo19
When you solve a quadratic equation, in some cases you factor. Right.

Well your problem looks a lot like something like this: (X+a)(X+b)=0

and the solutions are: x=-a, x=-b

Can you see my meaning?
• Apr 30th 2009, 04:31 AM
ThaBeretta
Quote:

Originally Posted by VonNemo19
When you solve a quadratic equation, in some cases you factor. Right.

Well your problem looks a lot like something like this: (X+a)(X+b)=0

and the solutions are: x=-a, x=-b

Can you see my meaning?

So the domain would be the point (2,1), right? That point is located in the first quadrant, giving me the answer of "d".
• Apr 30th 2009, 04:43 AM
Sundae
Let secx = y
therfore, y = 2 & y = 1/2
Because both values are positive they are in the 1st and 4th quadrant.

in the first quadrant everything is positive, in second quadrant only sin/cosec is positive, in the third quadrant only tan/cot is positive and in 4th quadrant cos/sec is positive.

Is that what u were askin?
• Apr 30th 2009, 10:25 AM
ThaBeretta
So the correct answer is choice "b"?
• Apr 30th 2009, 10:30 AM
VonNemo19
yes
yes
• Apr 30th 2009, 10:58 AM
ThaBeretta
Okay, thank you.