Please help. 7) cos(sin^-1 3/5) 8) 1-tan^2 65deg=csc^2 25deg
Last edited by mr fantastic; Apr 27th 2009 at 07:32 PM. Reason: Moved from original thread
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Originally Posted by donnyB Please help. 7) cos(sin^-1 3/5) 8) 1-tan^2 65deg=csc^2 25deg 7) cos(sin^-1 3/5) 8) 1-tan^2 65deg=csc^2 25deg Should be like below. $\displaystyle 1+\tan^{2}65^o = \csc^{2}25^o$
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