Please help:
4) sin-1 (square root of 5 over 3)
5) cot pie over 12
6) sint= 1/4. 0<t< pie over 2 and sin t is given.
4) sin-1 (square root of 5 over 3)
Do you mean $\displaystyle \sin^{-1}(\frac{\surd5}{3})$
5) cot pie over 12
You should find $\displaystyle \tan\frac{\pi}{12}$ 1st, then find its reciprocal.
You can you your scientific calculator
or
$\displaystyle \tan\frac{\pi}{6} =\frac{2\tan\frac{\pi}{12}}{1-\tan\frac{\pi}{12}}$ where $\displaystyle \frac{\pi}{6}$ is a special angle.
6) sint= 1/4. 0<t< pie over 2 and sin t is given.
That means it is in the 1st quadrant.