square root of 7x^2-448 x= 8sec theta
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Originally Posted by jumpman23 square root of 7x^2-448 x= 8sec theta I don't think you have expressed the problem very clearly. Are you trying to rewrite $\displaystyle \sqrt{7x^2-448}$ given $\displaystyle x=8\sec\theta?$ In that case, substitute, and note that $\displaystyle \sec^2\theta-1=\tan^2\theta.$
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