Find the exact value of sin2x. Sinx = (-4/7)
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Originally Posted by jumpman23 Find the exact value of sin2x. Sinx = (-4/7) You should know from class that $\displaystyle \sin(2x)=2\sin(x)\cos(x)$. You already known sin(x). To find cos(x) you can use the info already given to draw a right triangle and solve for the missing leg needed to find cos(x).
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