I had a question similar to this yesterday but I cant figure this one out.
what are the equations of the asymptotes for the function
y=(3)(cot)(3)(pi)(x)
y=
3 sin 3 pi x
3 cos 3pi x
one of the asympotes is found by making the bottom = 0
so I get
x cannot be apx. = .1667
but how can I find the equation for the asymptotes from that?
answer is either
x=n
x=n/2
x=n/3
x=2n
x=3n
thanks for any help.