I had a question similar to this yesterday but I cant figure this one out.

what are the equations of the asymptotes for the function

y=(3)(cot)(3)(pi)(x)

y=

3 sin 3 pi x

3 cos 3pi x

one of the asympotes is found by making the bottom = 0

so I get

x cannot be apx. = .1667

but how can I find the equation for the asymptotes from that?

answer is either

x=n

x=n/2

x=n/3

x=2n

x=3n

thanks for any help.