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Math Help - Please simplify

  1. #1
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    Please simplify

    (1+sinx/cosx)-(cosx/sinx-1)

    Please simply this
    This means no trig function in the denominator.

    Thanks!
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  2. #2
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    i can't get the denominator clear i keep getting
    -(sinx+1)/cosx or -cosx/(sinx-1)
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  3. #3
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    the final answer would be (1+sinx)-(cosx)

    or you can write it as 1+sinx-cosx without the brackets
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  4. #4
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    I'm arriving at a different result...

    (1+\frac{sinx}{cosx}) - (\frac{cosx}{sinx}-1)

    1 + \frac{sinx}{cosx} - \frac{cosx}{sinx} +1

    \frac{sin^2{x}}{sinxcosx} - \frac{cos^2{x}}{sinxcosx}+2

    \frac{sin^2{x}-cos^2{x}}{(\frac{1}{2})2sinxcosx} +2

    As {cos^2{x}-sin^2{x}} = cos2x and 2sinxcosx=sin2x, we have:

    -2\frac{cos2x}{sin2x} +2

    \therefore-2cot2x + 2
    Last edited by Referos; April 26th 2009 at 06:28 PM. Reason: latex
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  5. #5
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    Quote Originally Posted by decet View Post
    (1+sinx/cosx)-(cosx/sinx-1)

    Please simply this
    This means no trig function in the denominator.

    Thanks!
    Please post your expressions more clearly. Do you mean \frac{1 + \sin x}{\cos x} - \frac{\cos x}{\sin x - 1} ?
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