what are the equations of the asymptotes for the function y=tan((2pi)/4)x where 0<x<4
I have trouble with this style of question whether it be find the x intercepts etc.
I got the normal asymptotes (pi/2, 3pi/2, etc.)
Edit-b=pi/2
but if i multiply pi/2 by pi/2, 3pi/2 It gives me the wrong answer.
HOw do I solve these kind of questions?
Thanks.
A vertical asymptote is a vertical line that passes through the value of x for which the function is undefined. When you're function has the form of a fraction, it will obviously be undefined when the denominator is equal to zero. tan can be written in the form of a fraction. I told you to solve when the denominator of this fraction is equal to zero.
x = 1 is one solution to the equation I told you to solve. There are others lying in the domain [0, 4].
wow ok I think I understand, so to find the asymptotes do I multiply 1 by the b value? ie
pi/2, pi, 3pi/2, 2pi?
I have graphed it and the 1'st asymptote appears to be 1, then every 2, like 1,3,5...
so I guess since the period is 2, it's the 1 "first asymptote" plus the period (2) = 1,3,5 but since x is 0<x<4 its 1,3.
So when you solve for x like you got me to do it will always give the first asymptote/zero?
I 100% understand how to solve this now, (thanks very much.)
I am just asking if when you solve an equation for an x value like this equation "or any other equation" that has multiple x values, which x value will you get, the first, the closest to y=0 etc.
this is just purley out of curiosity.
an example could be (x-5)^2-4=0
x=8
why does solving for x give you 8 and not 4?