dv/dt = 3/[t((t^2)-1)] t>0, v(2) = 0
dv = integral 3/[t((t^2)-1)] dt
v = 3sect^-1 + C
3sec(-2)^-1 = -C
How do I evaluate inverse secant?! Is there any simple rule to go by just looking at the unit circle? My teacher says the answer is c = -pi.
dv/dt = 3/[t((t^2)-1)] t>0, v(2) = 0
dv = integral 3/[t((t^2)-1)] dt
v = 3sect^-1 + C
3sec(-2)^-1 = -C
How do I evaluate inverse secant?! Is there any simple rule to go by just looking at the unit circle? My teacher says the answer is c = -pi.