Sitting here studying for a final exam this week, and I am SOO bad at identities. Maybe I just don't know them well enough.

Anyhow,

*Find the solutions to the following:*
$\displaystyle sec^2x = 2secx$

I got this far...or maybe it's all wrong, I duno.

$\displaystyle 1+tan^2x = 2secx$ * from a Pythagorean identity

$\displaystyle 1+tan^2x = \frac{1}{2cosx}$ * from the reciprocal of sec?

$\displaystyle 1+tan^2x (cos2x-sin2x) $ *cross multiplied and double angle formula? I feel this wasn't a good move, haha.

Thanks in advanced!