..Quote:

Originally Posted byAnother user. Dont ask.

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- Apr 20th 2009, 01:06 AMmr fantasticFind exact sine valueQuote:

Originally Posted by**Another user. Dont ask.**

- Apr 20th 2009, 01:16 AMred_dog
You can use this: $\displaystyle \sin\frac{x}{2}=\sqrt{\frac{1-\cos x}{2}}$ and $\displaystyle \cos\frac{x}{2}=\sqrt{\frac{1+\cos x}{2}}$

$\displaystyle \sin\frac{\pi}{16}=\sqrt{\frac{1-\cos\frac{\pi}{8}}{2}}$

$\displaystyle \cos\frac{\pi}{8}=\sqrt{\frac{1+\cos\frac{\pi}{4}} {2}}$ - Apr 20th 2009, 02:05 AMmr fantastic
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