Why the equation $\displaystyle sin^-1(x)= cos^-1(2)$ cannot have a solution? (sin expontial -1) x = (cos exponential -1)2
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Originally Posted by darkmoon123 Why the equation $\displaystyle sin^-1(x)= cos^-1(2)$ cannot have a solution? (sin expontial -1) x = (cos exponential -1)2 $\displaystyle \cos^{-1}(2)$ does not have a real value.
Originally Posted by darkmoon123 Why the equation $\displaystyle sin^-1(x)= cos^-1(2)$ cannot have a solution? The cosine outputs values only between -1 and +1. The inverse-cosine function can take inputs only between -1 and +1. As such, the right-hand side of your equation is without mathematical meaning, which makes the entire equation nonsensical, and thus unsolveable.
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