Try looking at your addition formulas and the problem doesn't seem so tough any more. I could solve it for you but that wouldn't be any fun!
heres my working but I dont seem to get the right answers.
As tanX is −ve, X is in the 2nd and 4th quadrants
so the solutions between −245<X ≤ 565
should one of the solutions be 27 ?
in the fourth qudrant = 360-27 = 333
second quadrant = 180-27 = 153
but I have to get all the solutions up to 565 , how do I do that ?
The correct answer are; X= −207, −27, 153, 333, 513,
can you explain how they get -27, -207 and 513 from ?