I have to express the given trigonometric function in terms of the indicated function.

cos theata in terms of sec theata.

I have no clue, please help.

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- April 18th 2009, 07:50 PMscottsw1Trig problem
I have to express the given trigonometric function in terms of the indicated function.

cos theata in terms of sec theata.

I have no clue, please help. - April 18th 2009, 07:58 PMJhevon
- April 18th 2009, 08:02 PMlekhabhatt81
All i know is sec is the inverse of cos. see, if it works for you and help you solve your problem.

- April 18th 2009, 08:07 PMJhevon
- April 18th 2009, 08:16 PMlekhabhatt81
You are indeed correct. Sec is the reciprocal of cos. thanks buddy! :)

- April 19th 2009, 06:51 AMscottsw1
I am lost, please help. I know that sec=1 over cos, but what forumlua do I use to work the problem?

- April 19th 2009, 04:56 PMlekhabhatt81
could you put in the entire question? because with what you have put up... this is all that can be said, i guess.

- April 19th 2009, 07:59 PMscottsw1
Express the given trigometric function in terms of the indicated fucntion:

cos theta in terms of sec theata. - April 19th 2009, 08:10 PMJhevon
- April 20th 2009, 07:23 PMscottsw1
Please show me how to work the entire problem out. Thanks.

- April 20th 2009, 07:28 PMpickslides
- April 20th 2009, 08:48 PMscottsw1
Here is a photocopy of the problem:

http://farm4.static.flickr.com/3619/...c5c8a712db.jpg - April 21st 2009, 03:39 PMscottsw1
Does the link show an insight on how to solve the problem?

- April 21st 2009, 03:51 PMpickslides
I looked at the link.

Some of the problems are written very strangly. For example in ther first problem the first sec part of the equation seems to be raised to the power of something. But what?