I've been trying to figure this out for hrs now, somebody please assist me. sin^3 alpha + cos^3 aplha/ sin alpha + cos alpha = 1- sin alpha cos alpha
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Originally Posted by dmak263 I've been trying to figure this out for hrs now, somebody please assist me. sin^3 alpha + cos^3 aplha/ sin alpha + cos alpha = 1- sin alpha cos alpha Remember that a^3 +b^3 = (a+b)(a^2+b^2-ab) Put a =sin(alpha) , b = cos(alpha) Remembering that sin^2(alpha)+cos^2(alpha) = 1 ----------------------------------------- So the fraction becomes Now this = Adarsh
thank you.
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