# area of the triangle

• Apr 15th 2009, 05:31 PM
amanda0603
area of the triangle
hello all!
If anybody could helo i'd appreciate it!
For B=28degrees50minutes, a=13.5, b=8
I got that it was an ambiguous case and had 1 solution. Just wanted to see if I got that correct...

Also solve this triangle....

B=36.9degree
b=5.40
a=19.9

I got that it would not have a solution b/c it give you like 2.2 and once you do the arcsin, it falls outside of the interval (-1,1)....I just wanted to see if that was correct?

thanks so much!!!!!!
• Apr 15th 2009, 06:07 PM
skeeter
Quote:

Originally Posted by amanda0603
hello all!
If anybody could helo i'd appreciate it!
For B=28degrees50minutes, a=13.5, b=8
I got that it was an ambiguous case and had 1 solution. Just wanted to see if I got that correct...

two solutions, because
$\textcolor{red}{a\sin{B} < b < a}$

Also solve this triangle....

B=36.9degree
b=5.40
a=19.9

I got that it would not have a solution b/c it give you like 2.2 and once you do the arcsin, it falls outside of the interval (-1,1)....I just wanted to see if that was correct?

correct, no triangle is possible because
$\textcolor{red}{b < a\sin{B}}$

.