sin^6 -cos^6 = (2sin^2 -1)(1-sin^2+sin^4) help me prove this question pls.. tq
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Originally Posted by teckyuan sin^6 -cos^6 = (2sin^2 -1)(1-sin^2+sin^4) help me prove this question pls.. tq Start by noting that $\displaystyle \sin^6 x - \cos^6 x = \left( \sin^2 x\right)^3 - \left( \cos^2 x\right)^3$ and use the difference of two cubes formula.
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