Originally Posted by
skeske1234
$\displaystyle \cot x+\tan x=2\csc 2x$
LS:
$\displaystyle \cot x+\tan x=$
$\displaystyle \frac{\cos x}{\sin x}+\frac{\sin x}{\cos x}=$
$\displaystyle {\color{red}\frac{1}{\sin x \cos x}=}$
RS:
Try this instead: Recall that $\displaystyle \sin 2x = 2 \sin x \cos x$
$\displaystyle =\frac{2}{\sin 2x}$
$\displaystyle =\frac{2}{2 \sin x \cos x}$
$\displaystyle {\color{red}=\frac{1}{\sin x \cos x}}$