sin^2(x)=sinx How would I go about answering this? Would it work if I substitute x?
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Originally Posted by Jd09 sin^2(x)=sinx How would I go about answering this? Would it work if I substitute x? this is a quadratic in $\displaystyle \sin x$. to see this, let $\displaystyle a = \sin x$, then you have $\displaystyle a^2 = a$ $\displaystyle \Rightarrow a^2 - a = 0$ now what?
I had done the same, using the 'm' as a variable but I am not sure where to go on to next.
Originally Posted by Jd09 I had done the same, using the 'm' as a variable but I am not sure where to go on to next. you should review algebra. at the very least, if you don't know what to do, apply the quadratic formula. in this case, it is overkill though $\displaystyle m^2 - m = 0$ $\displaystyle \Rightarrow m(m - 1) = 0$ $\displaystyle \Rightarrow m = 0 \text{ or } m - 1 = 0$
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