# Math Help - Solving a quadratic trig equation

1. ## Solving a quadratic trig equation

Could someone help me with this question?

2sin²(x) - √3 sin(x) = 0

I am trying to solve for values of x.

so far I have done the following, however, I am unsure if this is correct.

let ' m ' = sinx

therefore...

m² - √3 = 0

2. Originally Posted by Jd09
Could someone help me with this question?

2sin²(x) - √3 sin(x) = 0

I am trying to solve for values of x.

so far I have done the following, however, I am unsure if this is correct.

let ' m ' = sinx

therefore...

m² - √3 = 0
it would be $2m^2 - \sqrt 3 m = 0$ would it not?

3. It should be $2m^2 - \sqrt{3}m = 0$

$\Rightarrow m(2m-\sqrt{3}) = 0$

Either $m = 0$ or $m = \frac{\sqrt{3}}{2}$

So you need to simply solve $\sin{x}=0$ and $\sin{x}=\frac{\sqrt{3}}{2}$